If Ka = 1.0 × 10^-6 and Kw = 1.0 × 10^-14, what is Kb?

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Multiple Choice

If Ka = 1.0 × 10^-6 and Kw = 1.0 × 10^-14, what is Kb?

Explanation:
In water, for a conjugate acid–base pair, Ka times Kb equals Kw. So Kb = Kw / Ka. Plugging in the values: Kb = (1.0 × 10^-14) / (1.0 × 10^-6) = 1.0 × 10^-8. This shows that the conjugate base is relatively weak, consistent with the given acid being moderately weak.

In water, for a conjugate acid–base pair, Ka times Kb equals Kw. So Kb = Kw / Ka. Plugging in the values: Kb = (1.0 × 10^-14) / (1.0 × 10^-6) = 1.0 × 10^-8. This shows that the conjugate base is relatively weak, consistent with the given acid being moderately weak.

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